Cheat Sheet for F

Cheat Sheet for F=ma

Solving for Force (F)

Given Information: An object with a mass of 270kg is dropped with an acceleration of 9.8 m/sec². With how much force does that object hit the ground?

Step 1. Write the formula F=ma

Step 2. List Values m= 270kg

A= 9.8 m/sec²

F= ?

Step 3. Substitute values into formula F= 270kg (9.8 m/sec²)

Step 4. Do the math

a. multiply mass x acceleration F= 2646 kg x m/sec²

Step 5 Convert the label F= 2646 N

Step 6 Circle your answer F= 2646 N

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Solving for Mass (m)

Given Information: An object with a force of 2646 N is dropped with an acceleration of 9.8 m/sec². How much mass does the object have?

Step 1. Write the formula F=ma

Step 2. List Values F= 2646 N

M= ?

A= 9.8m/sec²

Step 3. Substitute values into formula 2646 N= m (9.8 m/sec²)

Step 4. Do the math

a. You need to get the mass by itself, so

divide each side by the acceleration. 2646N = m(9.8m/sec²)

9.8m/sec² 9.8 m/sec²

b. Convert N into kg x m/sec² 2646kg x m/sec² = m(9.8m/sec²)

9.8m/sec² 9.8 m/sec²

c. Do the math including the canceling of

labels 270kg = m

Step 5 Circle your answer 270kg = m

Solving for Acceleration (a)

Given Information: An object with a force of 2646 N has a mass of 270kg 9.8 m/sec². How much acceleration does the object have?

Step 1. Write the formula F=ma

Step 2. List Values F= 2646 N

M= 270kg

A= ?

Step 3. Substitute values into formula 2646 N= 270kg (a)

Step 4. Do the math

a. You need to get the acceleration by itself,

so divide each side by the mass. 2646N = 270kg (a)

270kg 270kg

b. Convert N into kg x m/sec² 2646kg x m/sec² = 270kg(a)

270kg 270kg

c. Do the math including the canceling of

labels 9.8m/sec² = a

Step 5 Circle your answer 9.8m/sec² = a